
By M. V. Volkenstein
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Example text
Hence, the reaction rate depends on the temperature, increasing with an increase in temperature. Let us consider a very simple reaction in the gaseous phase H2 + i 2 -> 2HI where H is hydrogen, and I iodine. The rate of this reaction is v = kCHXh (35) where CH2, Cl2 are the concentrations of hydrogen and iodine, and k is the rate constant of reaction. \ *ΧΛ~ RT) ^r exp (l) ex p(-§) w where R is the gas constant; Ga, 5 a , // a are correspondingly the free energy, entropy, and enthalpy of activation; and NA is Avogadro's Fig.
The rigorous solution of the problem, with the help of the Schrodinger equation, is En == hv 2 + n nh u, == 0,1,2 . . (23) The nonrigorous solution (22) is similar to the rigorous solution (23): the energy levels of the oscillator are equidistant and the distance between neighboring levels is constant. In solution (22), the distance between neighboring levels is E n+ t En - 7T 4" h v == In the strict solution, E n+t - En == hv There is a difference in the numeral multiplier, but the law of quantization is reproduced well.
The wall becomes equilibrated again in a new position L' = L + AL. The corresponding work is W=(f -f)(L' Am U ' 3 - L) L3) (51) 54 Chapter n' I nI -« 1 0—O L 6 n' n ► ** L ► -< ±L· L+AL ** Fig. 20 Scheme ECI. This process is shown schematically in Fig. 20. The shift of the wall is followed by the decrease of electronic energy, which is inversely proportional to the square of the width L of the box. The wall represents the heavy atomic nuclei. Their displacements in a biopolymer reduce to a change of conformation.